10x^2-20x+11=0

Solution for 10x^2-20x+11=0 equation:

Simplifying
10x2 + -20x + 11 = 0

Reorder the terms:
11 + -20x + 10x2 = 0

Solving
11 + -20x + 10x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
10 the coefficient of the squared term: 

Divide each side by '10'.
1.1 + -2x + x2 = 0

Move the constant term to the right:

Add '-1.1' to each side of the equation.
1.1 + -2x + -1.1 + x2 = 0 + -1.1

Reorder the terms:
1.1 + -1.1 + -2x + x2 = 0 + -1.1

Combine like terms: 1.1 + -1.1 = 0.0
0.0 + -2x + x2 = 0 + -1.1
-2x + x2 = 0 + -1.1

Combine like terms: 0 + -1.1 = -1.1
-2x + x2 = -1.1

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -1.1 + 1

Reorder the terms:
1 + -2x + x2 = -1.1 + 1

Combine like terms: -1.1 + 1 = -0.1
1 + -2x + x2 = -0.1

Factor a perfect square on the left side:
(x + -1)(x + -1) = -0.1

Can't calculate square root of the right side.

The solution to this equation could not be determined.